Question

Which of the following is the correct rate of climb equation?

(a) τu-\(\frac{1}{2}\)[u^3+u^-1]=Emaxv

(b) τ-\(\frac{1}{2}\)[u^2+u^-2]=Emaxsinγ2

(c) τ+\(\frac{1}{2}\)[u^2+u^-2]=Emaxsinγ2

(d) τu-\(\frac{1}{2}\)[u^3+u^-1]=Emaxv

This question was posed to me during an online interview.

My doubt stems from Climb and Descent Performance with Thrust-Producing Engines topic in division Climb and Descent Performance of Aircraft Performance

Answer 1

The correct choice is (d) τu-\(\frac{1}{2}\)[u^3+u^-1]=Emaxv

Best explanation: The correct rate of climb equation is given by τu-\(\frac{1}{2}\)[u^3+u^-1]=Emaxv where τ is dimensionless thrust, u is airspeed, Emax is endurance and γ is the angle at which the force is acting on the aircraft.