Right answer is (a) True
To explain I would say: In cruise method 2 the range factor is given by R=\(\Big[\frac{V_{mdi}}{C}E_{max}\Big]\Big\{\frac{2u^3}{u^4+1}\Big\}2\Big(1-\omega^{\frac{-1}{2}}\Big)\) where \(\Big[\frac{V_{mdi}}{C}E_{max}\Big]\) is range factor and is same of that in cruise method 1 but overall range of cruise method 2 is less than that of cruise method 1.