Question

Consider 2 reverse biased diodes. If the ratio of applied reverse bias voltages is 0.5, find the ratio of transition capacitances of the 2 diodes.

(a) 2

(b) 4

(c) 1.31

(d) 2.6

The question was asked in class test.

My question is taken from Transition Capacitance in chapter Diode Circuit of Analog Circuits

Answer 1

The correct answer is (c) 1.31

The best explanation: \(\frac{C_{T1}}{C_{T2}} = (\frac{V2}{V1})^{\frac{1}{2.5}} \)

\(\frac{C_{T1}}{C_{T2}}  = 2^{\frac{1}{2.5}}\) = 1.31.