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If L1 and L2 are the inductance used in the Hartley oscillator, the effective inductance in the equation of frequency calculation is equal to (Without considering mutual inductance).

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If L1 and L2 are the inductance used in the Hartley oscillator, the effective inductance in the equation of frequency calculation is equal to (Without considering mutual inductance).

(a) (L1×L2)/(L1+L2)

(b) L2^2/(L1+L2)

(c) L1+L2

(d) L1-L2

This question was posed to me in exam.

My query is from Hartley Oscillator-2 in portion Oscillators of Analog Circuits

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Correct answer is (c) L1+L2

Easiest explanation: Inductance L1 and L2 are series and hence effective inductance without mutual inductance will be L1+L2.

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