The correct choice is (a) 32.6
To explain I would say: The voltage gain is given by RL/(1/gm + RL) where RL is the 50 Ω load. Now, we see that if the voltage gain is .25, gm is 1/175. Now, gm is \(\sqrt{(2* µ_nC_{ox} * (W/L) * Id)}\) where (W/L) is the aspect ratio, Id is the drain current. We have all the values and the aspect ratio becomes 32.6.