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In the given circuit, what is the value of IC if the BJT is made of Silicon?

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In the given circuit, what is the value of IC if the BJT is made of Silicon?

(a) 2.01 mA

(b) 2.01 uA

(c) 10.05 mA

(d) 10.05 uA

I got this question in an internship interview.

The doubt is from BJT DC biasing in division BJT Biasing of Analog Circuits

1 Answer

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The correct answer is (a) 2.01 mA

To explain: Consider the BJT to be in saturation. Then IC=20-0.2/2k=9.9 mA

And IB=20-0.8/430k=0.044 mA

IBMIN=ICSAT/β=5.09/50=0.198mA which is greater than above IB.

Hence transistor is in the active region.

Thus IC=βIB.

VBE=0.7V

IB=20-0.7/430=44.88μA

IC=50×44.88=2.24 mA.

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