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An AM signal is represented by x(t) = (30 + 2Sin(700πt)) Cos(2πt x 10^2t)V. What is its sideband power?

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An AM signal is represented by x(t) = (30 + 2Sin(700πt)) Cos(2πt x 10^2t)V. What is its sideband power?

(a) 4W

(b) 1W

(c) 3W

(d) 2W

This question was posed to me at a job interview.

This is a very interesting question from Power Relations in AM Waves in division Amplitude Modulation of Analog Communications

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The correct choice is (b) 1W

The explanation is: Sideband power i = (m^2* Pc)/2 = (Pt – Pc) i.e. 451 – 450 = 1W.

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