Right answer is (c) increases by factor 9
Explanation: From Friss transmission equation,
\(\frac{P_r}{P_t} = \frac{G_t G_r λ^2}{(4\pi R)^2} = \frac{G_t G_r c^2}{(4\pi Rf)^2}\)
\(\frac{P_{r1}}{P_{r2}} = \frac{f_2^2}{f_1^2} = \frac{(f/3)^2}{f^2} = \frac{1}{9}\)
Pr2=9Pr1