Correct answer is (b) Independent, independent
To explain I would say: Due to symmetric distribution in isotropic source, there will be no θ, ф components. Only radial component will be present. \( P_{total \,rad}=∯ Usinθdθd∅=4πU (For \,θ: 0 \,to \,π, \phi: 0 \,to\, 2π).\)
∴ Radiation intensity \(U=\frac{P_{total \,rad}}{4π}\)