Right option is (a) 30mV/m
Explanation: For isotropic radiator, power per unit area = \(\frac{P_t}{4πr^2}\) — (1)
From pointing theorem, \(P=\frac{\mid E_{max}^2\mid}{2\eta}\), where η=120π. —– (2)
Equating (1) & (2) and Erms=Emax/√2, we get
\(E_{rms}=\frac{\sqrt{30P_t}}{r}=\frac{\sqrt{30×3000}}{10000}=30mV/m.\)