Question

CO=40%, H2=12%, CO2=6%, CH2=2%, N2=50% are the components in the coal. What will be the composition of the dry flue gas, if the 50% excess air was used for burning 100m^3 of gas?

(a) CO2=14.9%, N2=80%, O2=5.2%

(b) CO2=12.2%, N2=70.8%, O2=6.5%

(c) CO2=14.9%, N2=79.9%, O2=5.2%

(d) CO2=13%, N2=77%, O2=75

The question was asked in semester exam.

My question comes from Fuel Technologies Problems in chapter Fuel Technologies of Applied Chemistry

Answer 1

Correct option is (c) CO2=14.9%, N2=79.9%, O2=5.2%

For explanation I would say: Form a table formulating the actual components in 100m^3, combination reactions and volume required and % of dry gas. Find total volume of gas. Later calculate the volume of oxygen in excess air by calculating the volume of dry products. Add the dry products combinations to get the total products combination and then calculate the carbon dioxide, nitrogen and oxygen percentages.