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The coal sample contains=80%; H=4%; O=2%; N=12%; S=2%, the remainder is ash and then calculate the volume of air required for perfect combustion of 1kg of fuel assuming STP conditions.

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The coal sample contains=80%; H=4%; O=2%; N=12%; S=2%, the remainder is ash and then calculate the volume of air required for perfect combustion of 1kg of fuel assuming STP conditions.

(a) weight of oxygen required=10.65kg; volume of the oxygen=8725l

(b) weight of oxygen required=11.25kg; volume of the oxygen=8500l

(c) weight of oxygen required=11.25; volume of the oxygen=8200l

(d) weight of oxygen required=10.65kg; volume of the oxygen=8166.6l

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I would like to ask this question from Fuel Technologies Problems in chapter Fuel Technologies of Applied Chemistry

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Correct option is (d) weight of oxygen required=10.65kg; volume of the oxygen=8166.6l

To elaborate: The total weight of oxygen required for combustion is calculated by taking every component equation. It will be 2.45kg and then calculate the volume of oxygen. At STP conditions 32g of oxygen occupies 22.4l volume. Calculate for 2450g and then find weight of oxygen required as we know 100kg of gas requires 23kg of oxygen.

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