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If a sample water has not supplied any heat and having impurities as follows: Mg(HCO3)2=50 mg of CaCO3, MgSO4 = 100mg of CaCO3, CaCl2=200mg of CaCO3, Ca(NO3)2=100mg of CaCO3. Calculate the lime required for treatment of 10000 litres of water.

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If a sample water has not supplied any heat and having impurities as follows: Mg(HCO3)2=50 mg of CaCO3, MgSO4 = 100mg of CaCO3, CaCl2=200mg of CaCO3, Ca(NO3)2=100mg of CaCO3. Calculate the lime required for treatment of 10000 litres of water.

(a) 1.82Kg

(b) 1.50Kg

(c) 1.45Kg

(d) 1.48Kg

I have been asked this question at a job interview.

I need to ask this question from Problems, Units and Formulae in chapter Water of Applied Chemistry

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Right option is (d) 1.48Kg

The best explanation: Lime needed is 0.74[temp Ca hardness+temp of Mg hardness+perm Mg hardness]. So, 0.74(0+2*50+100)=148mg/litre. Lime requirement for 10000 litres of water is 148*10000mg=1.48Kg.

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