Correct answer is (d) 141.52°
The explanation: (ωB / ωA) = (cos α) / (1 – cos^2θ sin^2α) where A = driving shaft and B = driven shaft and α is the angle between shaft A and shaft B. θ is the angle through which the shaft A rotates. Velocity ratio is unity when tanθ = ± \(\sqrt{cos\alpha} = ± \sqrt{cos35}\) = ± 0.90 i.e. θ = 42.145°, 222.145°, 317.85°, and 137.85°.