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Find the allowable circumferential stress for the material having Sut=190 and the Factor of safety is 4.

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Find the allowable circumferential stress for the material having Sut=190 and the Factor of safety is 4.

(a) 47.5 N/mm^2

(b) 47.5N/m^2

(c) 760N/mm^2

(d) 760N/m^2

This question was posed to me in an interview for internship.

I want to ask this question from IC Engine topic in chapter Design of IC Engine Components of Automotive Engine Design

1 Answer

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Correct answer is (a) 47.5 N/mm^2

The best I can explain: σt=\(\frac{S_{ut}}{F_s}\)

                           = 190/4

                           =47.5N/mm^2

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