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Feed of a reactor has 0.75 mass fraction of O2 and some SO2, if the product rate is 1000 Kg/hr then what is the rate of SO2 in the feed?

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Feed of a reactor has 0.75 mass fraction of O2 and some SO2, if the product rate is 1000 Kg/hr then what is the rate of SO2 in the feed?

(a) 100 Kg/hr

(b) 250 Kg/hr

(c) 750 Kg/hr

(d) 1000 Kg/hr

This question was posed to me during an online exam.

The origin of the question is Multiple Component Systems topic in division Introduction to Material Balances of Basic Chemical Engineering

1 Answer

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Best answer
Correct option is (b) 250 Kg/hr

The best explanation: Feed rate = Product rate = 1000 Kg/hr, => Rate of SO2 = (1 – 0.75)*1000 = 250 Kg/hr.

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