Question

A reactor has two feed streams with the ratio of their rate as 1:9 and has O2 and O3 with the mass fraction of 0.6 and 0.4 in stream 1 and 0.2 and 0.8 in stream 2, what is the mass fraction of O2 in the product side?

(a) 0.24

(b) 0.48

(c) 0.72

(d) 0.96

This question was posed to me in exam.

My doubt is from Multiple Component Systems in portion Introduction to Material Balances of Basic Chemical Engineering

Answer 1

The correct answer is (a) 0.24

The explanation: Let the stream rates be 1 Kg/hr and 9 Kg/hr, => mass fraction of O¬2 in product side = (1*0.6 + 9*0.2)/(1 + 9) = 0.24.