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A current of 5A flows in a resistor of 2 ohms. Calculate the energy dissipated in 300 seconds in the resistor.

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A current of 5A flows in a resistor of 2 ohms. Calculate the energy dissipated in 300 seconds in the resistor.

(a) 15kJ

(b) 15000kJ

(c) 1500J

(d) 15J

I got this question in an interview for internship.

The query is from Power in portion Simple DC Networks of Basic Electrical Engineering

1 Answer

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Right option is (a) 15kJ

For explanation I would say: P=I^2R =5^2*2=50W.

E= Pt=50*300=15000J=15kJ.

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