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Calculate the energy in the 5 ohm resistor in 20 seconds.

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in Basic Electrical Engineering by (88.7k points)
Calculate the energy in the 5 ohm resistor in 20 seconds.

(a) 21.5kJ

(b) 2.15kJ

(c) 2.15J

(d) 21.5kJ

I got this question in homework.

This interesting question is from Energy topic in chapter Simple DC Networks of Basic Electrical Engineering

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The correct option is (a) 21.5kJ

For explanation I would say: The current in the circuit is equal to the current in the 5 ohm resistor since it a series connected circuit, hence I=220/(5+10)=14.67A. P=I^2R = 14.67^2*5=1075.8W. E=Pt = 1075.8*20 = 21516J=21.5kJ.

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