Question

The relationship between K^‘eq and ∆G^‘° is?

(a) ∆G^‘° = RTlnK^‘eq

(b) ∆G^‘° = -RTK^‘eq

(c) ∆G^‘° = RK^‘eq

(d) ∆G^‘° = -RK^‘eq

I had been asked this question at a job interview.

Query is from Bioenergetics and Thermodynamics in portion Principles of Bioenergetics and Glycolysis of Biochemistry

Answer 1

Right choice is (b) ∆G^‘° = -RTK^‘eq

Easy explanation: If the system is in equilibrium ∆G° = 0 and ∆G^‘° = -RTK^‘eq is the correct relation between K^‘eq and ∆G^‘°.