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The flux linkage in coil 1 is 3 Wb and it has 500 turns and the current in coil 2 is xA, calculate the value of x if the mutual inductance is 750H.

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The flux linkage in coil 1 is 3 Wb and it has 500 turns and the current in coil 2 is xA, calculate the value of x if the mutual inductance is 750H.

(a) 1A

(b) 2A

(c) 3A

(d) 4A

The question was asked during an online interview.

The above asked question is from Mutual Inductance in division Inductance in a DC Circuit of Basic Electrical Engineering

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The correct option is (b) 2A

The best explanation: We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.

I=3*500/750 = 2A.

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