Question

The flux linkage in coil 1 is 3Wb and it has x turns and the current in coil 2 is 2A, calculate the value of x if the mutual inductance is 750H.

(a) 300

(b) 400

(c) 500

(d) 700

This question was posed to me in an international level competition.

My enquiry is from Mutual Inductance topic in section Inductance in a DC Circuit of Basic Electrical Engineering

Answer 1

The correct option is (c) 500

Easiest explanation: We know that mutual inductance is the product of the number of turns in one coil and the flux linkages of that coil, divided by the current in the other coil.

N=750*2/3 = 500 turns.