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A circuit has a resistance of 2 ohms connected in series with a capacitance of 6F. Calculate the discharging time constant.

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A circuit has a resistance of 2 ohms connected in series with a capacitance of 6F. Calculate the discharging time constant.

(a) 3

(b) 1

(c) 12

(d) 8

This question was posed to me in my homework.

This intriguing question comes from Discharge of a Capacitor Through a Resistor topic in division Capacitance and Capacitors of Basic Electrical Engineering

1 Answer

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Right option is (c) 12

Explanation: The discharging time constant in a circuit consisting of a capacitor and resistor in series is the product of the resistance and capacitance = 2*6 = 12.

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