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A circuit has a resistance of 5 ohm connected in series with a capacitance of 10F. Calculate the discharging time constant.

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A circuit has a resistance of 5 ohm connected in series with a capacitance of 10F. Calculate the discharging time constant.

(a) 15

(b) 50

(c) 5

(d) 10

I have been asked this question in final exam.

The doubt is from Growth and Decay topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

1 Answer

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Best answer
Correct answer is (b) 50

Best explanation: The discharging time constant in a circuit consisting of a capacitor and resistor in series is the product of the resistance and capacitance = 5*10 = 50.

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