The correct answer is:
(b) 1×10^-7 M
Explanation: In pure water, the concentration of hydrogen ions (H⁺) is 1×10^-7 M at 25°C. This is because water undergoes autoionization, where a small fraction of water molecules dissociate into hydrogen ions (H⁺) and hydroxide ions (OH⁻):
H2O(l)⇌H+(aq)+OH−(aq)H_2O (l) \rightleftharpoons H^+ (aq) + OH^- (aq)H2O(l)⇌H+(aq)+OH−(aq)
At 25°C, the concentrations of H⁺ and OH⁻ in pure water are equal, each being 1×10^-7 M. This results in a neutral pH of 7, as pH is defined as the negative logarithm of the hydrogen ion concentration:
pH=−log[H+]\text{pH} = -\log[H^+]pH=−log[H+]
Since [H⁺] = 1×10^-7 M in pure water, the pH of pure water is 7.