The correct choice is (c) \(\nabla.\vec{V} = \frac{1}{\delta V}\frac{D(\delta V)}{dt} \)
To explain: For control volumes,
\(\frac{DV}{Dt}=\iiint_{V}(\nabla.\vec{V})dV\)
For infinitesimal elements, V can be represented as δ V. Therefore,
\(\frac{D(\delta V)}{Dt}=\iiint_{\delta V}(\nabla.\vec{V})dV\)
As the elements are infinitesimally small, ∇.\(\vec{V}\) is the same for all elements. Hence,
\(\frac{D(\delta V)}{Dt}=(\nabla.\vec{V})\delta V\)
\(\nabla \vec{V}=\frac{1}{\delta V} \frac{D(\delta V)}{Dt}\).