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Consider that our codon in place of being triplet was quadruplet. How many possible combinations could be there then?

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Consider that our codon in place of being triplet was quadruplet. How many possible combinations could be there then?

(a) 64

(b) 128

(c) 256

(d) 360

I have been asked this question in a job interview.

This intriguing question comes from Genetic Code in chapter Gene Expression : Translation of Cytogenetics

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Right option is (c) 256

For explanation: There are 4 DNA bases and triplet coodon so number of possible combinations id 4^3=64. Now if the codon was quadruplet the combinations would be 4^4=256.

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