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We know that caffeine helps to overcome M-Cdk activation checkpoint. What will be the fate of the cell treated with hydroxyl urea and caffeine in G1 phase?

(a) Cell will not divide

(b) Cell will become smaller in size

(c) Cell will divide with improper chromosome number

(d) Cell will undergo lysis

I have been asked this question in an international level competition.

The above asked question is from Overview of Cell Reproduction in division Chromosomal Changes During Meiosis of Cytogenetics

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Right option is (c) Cell will divide with improper chromosome number

Easy explanation: Hydroxyurea prevents DNA replication. When this is coupled with caffeine that helps overcome M-Cdk checkpoint it leads to improper chromosome distribution among the daughter cells.

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