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What is the phenotypic ratio in case of duplicate dominant epistasis?

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What is the phenotypic ratio in case of duplicate dominant epistasis?

(a) 9:3:4

(b) 12:3:4

(c) 15:1

(d) 9:7

I have been asked this question during a job interview.

My question is based upon Duplicate Epistasis in section Extension and Deviation from Mendelian Genetic Principles of Cytogenetics

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Right answer is (c) 15:1

The explanation: In case of duplicate dominant epistasis the normal 9:3:3:1 ratio is modified to give the ratio of 15:1. In this case the 1/16 represents homozygous recessive condition.

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