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500 kg of milk testing 6.5% fat to be standardized to 3.1% fat using skim milk containing 0.05% fat. Therefore, the quantity of skim milk required to be added to 500 kg whole milk will be?

(a) 557.38 kg

(b) 440 kg

(c) 850 kg

(d) 500 kg

The question was posed to me in a national level competition.

I'd like to ask this question from Standardization in division Building Blocks of Dairy Processing of Dairy Engineering

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Correct choice is (a) 557.38 kg

The best explanation: Thus mixing of 3.05 kg of 6.5% fat milk with 3.40 kg of the skim milk will yield 6.45 kg of milk containing the desired fat level i.e. 3.1%. Therefore, the quantity of skim milk required to be added to 500 kg whole milk will be (3.4 x 500)/3.05=3.05. Accordingly, 557.38 kg of 0.05% skim milk mixed with 500 kg of 6.5% fat whole milk will yield 1057.38 kg of milk having 3.1% fat.

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