Question

Calculate the I0 r.m.s for Single-phase Half Wave rectifier for R-L load (Highly inductive) using the data: Vm=110 V, ∝=16°, β=31°, R=1 Ω.

(a) 4.56 A

(b) 1.82 A

(c) 4.81 A

(d) 9.15 A

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Question is taken from Solid-State Switching Circuits in chapter Introduction to Solid-State Switching Circuits of Electric Drives

Answer 1

Right option is (b) 1.82 A

The explanation: In Half-wave controlled rectifier, the r.m.s value of the current is Vm(cos(∝) – cos(β))÷2πR=110(cos(16°) – cos(31°))÷6.28=1.82 A. The thyristor will conduct from ∝ to β.