Right answer is (c) 0 to 2^n – 1
To explain I would say: The maximum possible range of bit-count specifically in n-bit binary counter consisting of ‘n’ number of flip-flops is 0 to 2^n-1. For say, there is a 2-bit counter, then it will count till 2^2-1 = 3. Thus, it will count from 0 to 3.