Question

How many memory locations are addressed using 18 address bits?

(a) 165,667

(b) 245,784

(c) 262,144

(d) 212,342

This question was addressed to me during an interview.

This is a very interesting question from Programmable Read Only Memory in portion Memory Devices of Digital Circuits

Answer 1

The correct choice is (c) 262,144

Explanation: For n address bits, the memory location will consist of 2^n bits. Using 18 address bits, 2^18 = 262,144 (= 256 K) words are addressed.