Correct option is (d) |rxy(l)|≤\(\sqrt{r_{xx}(0).r_{yy}(0)}\)
For explanation: We know that, a^2rxx(0)+b^2ryy(0)+2abrxy(l) ≥0
=> (a/b)^2rxx(0)+ryy(0)+2(a/b)rxy(l) ≥0
Since the quadratic is nonnegative, it follows that the discriminate of this quadratic must be non positive, that is 4[r^2xy(l)- rxx(0) ryy(0)] ≤0 => |rxy(l)|≤\(\sqrt{r_{xx}(0).r_{yy}(0)}\).