Right option is (d) {14,16,14,16}
The explanation: We know that the circular convolution of two sequences is given by the expression
x(m)= \(\sum_{n=0}^{N-1}x_1 (n) x_2 (m-n)_N\)
For m=0, x2((-n))4={1,4,3,2}
For m=1, x2((1-n))4={2,1,4,3}
For m=2, x2((2-n))4={3,2,1,4}
For m=3, x2((3-n))4={4,3,2,1}
Now we get x(m)={14,16,14,16}.