Right option is (c) s=(1-z^-1)/T
To elaborate: The analog differentiator with output dy(t)/dt has the system function H(s)=s, while the digital system that produces the output [y(n)-y(n-1)]/T has the system function H(z) =(1-z^-1)/T. Thus the relation between s-domain and z-domain is given as
s=(1-z^-1)/T.