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What is the formula for the outer cylindrical heat dissipating surface of the magnet coils?

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What is the formula for the outer cylindrical heat dissipating surface of the magnet coils?

(a) outer cylindrical heat dissipating surface = 3.14 * outer diameter of coil + axial length of coil

(b) outer cylindrical heat dissipating surface = 3.14 + outer diameter of coil + axial length of coil

(c) outer cylindrical heat dissipating surface = 3.14 / outer diameter of coil + axial length of coil

(d) outer cylindrical heat dissipating surface = 3.14 * outer diameter of coil * axial length of coil

The question was posed to me in final exam.

My question is based upon Design of Magnet Coils in portion Design of Electromagnets of Design of Electrical Machines

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Correct choice is (d) outer cylindrical heat dissipating surface = 3.14 * outer diameter of coil * axial length of coil

To elaborate: The outer diameter of the coil is first calculated. Next, the axial length of the coil is next calculated and on substitution gives the outer cylindrical heat dissipating surface of the magnet coils.

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