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What is the formula of the inner cylindrical heat dissipating surface?

(a) inner cylindrical heat dissipating surface = length of mean turn * axial length of coil

(b) inner cylindrical heat dissipating surface = 2 *length of mean turn * axial length of coil

(c) inner cylindrical heat dissipating surface = length of mean turn / axial length of coil

(d) inner cylindrical heat dissipating surface =1 / length of mean turn * axial length of coil

I had been asked this question in an interview for internship.

Question is taken from Design of Magnet Coils in section Design of Electromagnets of Design of Electrical Machines

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Correct choice is (b) inner cylindrical heat dissipating surface = 2 *length of mean turn * axial length of coil

Explanation: The length of mean turn is first calculated. Next, the axial length of coil is calculated and on substitution gives the inner cylindrical heat dissipating surface.

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