Question

The design strength of tension member corresponding to gross section yielding is given by :

(a) γm0 fyAg

(b) γm0fy/Ag

(c) fy/Ag γm0

(d) fyAg/ γm0

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Answer 1

Correct answer is (d) fyAg/ γm0

For explanation: The design strength of tension member corresponding to gross section yielding is given by Tdg = fyAg/ γm0, where fy = yield strength of material in MPa, Ag = gross cross-sectional area in mm^2, γm0 = partial safety factor for failure in tension by yielding = 1.10.