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The additional factor to be added for angles for design strength of tension member corresponding to net section rupture is given by :

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The additional factor to be added for angles for design strength of tension member corresponding to net section rupture is given by :

(a) βAg0fyγm0

(b) βAg0fy/γm0

(c) βAg0γm0

(d) βAg0/fyγm0

This question was posed to me in final exam.

My doubt is from Angles Under Tension and Factors affecting Strength in portion Design of Tension Members of Design of Steel Structures

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Right answer is (b) βAg0fy/γm0

The explanation is: The design strength of angle section governed by tearing at net section is given by     Tdn = (0.9Ancfu/γm1) + βAg0fy/γm0 , where Anc = net area of connected leg, Ag0 = gross area of outstanding leg, fu = ultimate strength of material, γm1 = partial safety factor for failure due to rupture of cross section = 1.25, γm0 = partial safety factor for failure in tension by yielding = 1.10.

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