Correct answer is (c) 432.27 kN
The explanation is: fu = 410MPa, fy = 250MPa, γm0 = 1.1, γm1 = 1.25,
For ISA 125 x 75 x 10mm : gross area Ag = 1902 mm^2
Tensile strength due to gross section yielding, Tdg = Agfy/γm0 = 1902 x 250 x 10-3 / 1.1 = 432.27 kN.