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Calculate the value of Eo when pno=10^4cm^-3 and ppo=10^16cm^-3 at T=300K.

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Calculate the value of Eo  when pno=10^4cm^-3 and ppo=10^16cm^-3 at T=300K.

(a) 1meV

(b) 0.7meV

(c) 0.7eV

(d) 0.1meV

I had been asked this question in an online quiz.

The origin of the question is Band Structure of an Open-Circuited p-n junction topic in division Semiconductor-Diode Characteristics of Electronic Devices & Circuits

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Correct option is (c) 0.7eV

Explanation: Eo=kTln(ppo/pno)

Substituting the values, we get

Eo=0.7eV.

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