Question

In CE configuration, if the voltage drop across 5kΩ resistor connected in the collector circuit is 5V. Find the value of IB when β=50.

(a) 0.01mA

(b) 0.25mA

(c) 0.03mA

(d) 0.02mA

I have been asked this question in an internship interview.

The doubt is from The Common Emitter Configuration in section Transistor Characteristics of Electronic Devices & Circuits

Answer 1

Correct answer is (d) 0.02mA

The best explanation: IC=V across RL/RL=5V/5KΩ=1mA.

IB=IC/β=1/50=0.02mA.