Question

A transistor is connected in CE configuration. Collector supply voltage Vcc=10V, RL=800Ω, voltage drop across RL=0.8V, α=0.96. What is base current?

(a) 41.97µA

(b) 56.78µA

(c) 67.67µA

(d) 78.54µA

The question was posed to me in final exam.

This intriguing question comes from The Common Emitter Configuration in division Transistor Characteristics of Electronic Devices & Circuits

Answer 1

Correct choice is (a) 41.97µA

The explanation: Here, IC=0.8/800=1mA

 β= α/ (1-α)=0.96/1-0.96=24.

Now, IB=IC/ β=1/24=41.67µA.