Question

Which scheduling test is used to indicate that no scheduling exist even if there exist one?

(a) complex test

(b) simple test

(c) sufficient test

(d) necessary test

This question was addressed to me in unit test.

I need to ask this question from Classification of Scheduling Algorithms in division Embedded Operating System, Middleware and Scheduling of Embedded Systems

Answer 1

Right answer is (c) sufficient test

Easiest explanation: The sufficient condition indicates that no schedule exists even if there exist one and the necessary condition indicates that no schedule exists even if a schedule exists.