The correct option is (a) 1/21 [(H2/2) + (CO/2) + 2CH4 + 3C2H4] m^3/m^3 of fuel
Easiest explanation: Volumetric analysis of fuels hydrogen, carbon monoxide, methane, ethane, carbon dioxide and nitrogen is done and required minimum amount of oxygen is found for one m^3 of gaseous fuel:
O2 required/m^3 of fuel = 1/100[(H2/2) + (CO/2) + 2CH4 + 3C2H4] m^3
As atmospheric air contains 21% of O2 by volume, minimum air required t burn one m^3 of gaseous fuel is given by,
Minimum volume of air required (cm^3/m^3 of fuel):
= 1/100 [(H2/2) + (CO/2) + 2CH4 + 3C2H4] 100/21
= 1/21 [(H2/2) + (CO/2) + 2CH4 + 3C2H4] m^3/m^3 of fuel.