Question

Which is the common method to relate higher calorific value to lower calorific value?

(a) HCV = LCV + HV (nH2O, out / nfuel, in)

(b) LCV = HCV + HV (nH2O, out / nfuel, in)

(c) HCV = LCV + HV (nfuel, in/ nH2O, out)

(d) LCV = HCV + HV (nfuel, in/ nH2O, out)

The question was asked during an online exam.

I'd like to ask this question from Calorific Value of Fuels in chapter Steam Power Plant of Energy Engineering

Answer 1

Correct answer is (a) HCV = LCV + HV (nH2O, out / nfuel, in)

Explanation: HV – heat vaporization of water.

                       nH2O, out  – moles of water vaporized.

                       nfuel, in    – number of moles of fuel combusted.

High calorific value is equal to low calorific value plus, product of heat of vaporization of water and moles of water vaporized by moles of fuel combusted.