Question

The shaft power developed by the water passing through the prime mover is given by _______

(a) P =  \(\frac{mgH}{1000}\) × no^.

(b) P =  \(\frac{mgH}{10}\) × no^.

(c) P =  \(\frac{mgH}{100}\) × no^.

(d) P =  \(\frac{mgH}{n_{o^.}}\) × 1000

I got this question in an international level competition.

My question is from Hydrology topic in section Hydro Electric Power Plant of Energy Engineering

Answer 1

Right option is (a) P =  \(\frac{mgH}{1000}\) × no^.

To explain I would say: Where, m = Rate of water flow in kg/sec.

   H = Height of fall in meters.

   no = overall efficiency.