Question

Determine net calorific value of a volatile liquid fuel, having following results after using Boy’s calorimeter: Volume of the liquid fuel burnt = 0.152 m3, weight of the water used for cooling = 48.5 kg, Weight of the steam condensed = 91 gm, Temperature of inlet water = 35.2 ^0C and Temperature of outlet water = 42.6 ^0C?

(a) 2361.184 Kcal/m^3

(b) 2013.348 Kcal/m^3

(c) 2256.95 Kcal/m^3

(d) 2185.679 Kcal/m^3

This question was posed to me by my school teacher while I was bunking the class.

This question is from Determination of Calorific Value of Gaseous and Volatile Liquid Fuels topic in portion Fuels and Combustion of Engineering Chemistry II

Answer 1

Correct answer is (b) 2013.348 Kcal/m^3

The best I can explain: By using relation GCV = w(t2 –  t1)/ V,

We get GCV = 2361.184 Kcal/m^3

NCV = GCV – (m/V)×587

NCV = 2013.348 Kcal/m^3.