Question

Determine the gross calorific value (GCV) of a gas, having following results after using Boy’s calorimeter: Volume of the gaseous fuel burnt = 0.093 m^3, weight of the water used for cooling = 30.5 kg, Weight of the steam condensed = 31 gm, Temperature of inlet water = 26.1 ^0C and Temperature of outlet water = 36.5 ^0C?

(a) 3100 Kcal/m^3

(b) 3310 cal/gm

(c) 3410 Kcal/m^3

(d) 3780 Kcal/gm

The question was asked in examination.

Question is from Determination of Calorific Value of Gaseous and Volatile Liquid Fuels in chapter Fuels and Combustion of Engineering Chemistry II

Answer 1

Right answer is (c) 3410 Kcal/m^3

The best explanation: By using relation GCV = w(t2 –  t1)/ V,

We get GCV = 3410 Kcal/m^3.